What is the inverse of f(x)=x^2-2x+5 ?

The inverse of f(x)=x^2-2x+5 is 1+sqrt(x-4),1-sqrt(x-4)

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inverse of f(x)=x^2-2x+5

inverse

f (x) = x^{2} - 2 x + 5

1 + x - 4, 1 - x - 4

Solution steps

y = x^{2} - 2 x + 5

Replace

x

with

y

x = y^{2} - 2 y + 5

Solve for

y, x = y^{2} - 2 y + 5

1 + x - 4, 1 - x - 4

f (x) = 7 - 9 x

f (x) = \frac{x ^{2} + 5 x + 6}{x ^{2} - 3 x - 10}

f (x) = \frac{5 x}{x - 2}

y = 2 x + 3, (1, 5)

f (x) = \frac{2 x}{x ^{2} - 4}

What is the inverse of f(x)=x^2-2x+5 ?
The inverse of f(x)=x^2-2x+5 is 1+sqrt(x-4),1-sqrt(x-4)