What is x^2+y^2+8x-9y=6 ?

The solution to x^2+y^2+8x-9y=6 is Circle with (a,b)=(-4, 9/2),r= 13/2

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x^2+y^2+8x-9y=6

x^{2} + y^{2} + 8 x - 9 y = 6

(a, b) = (- 4, \frac{9}{2}), r = \frac{13}{2}

Solution steps

x^{2} + y^{2} + 8 x - 9 y = 6

Rewrite

x^{2} + y^{2} + 8 x - 9 y = 6

in the form of the standard circle equation

(x - (- 4))^{2} + (y - \frac{9}{2})^{2} = (\frac{13}{2})^{2}

Therefore the circle properties are:

(a, b) = (- 4, \frac{9}{2}), r = \frac{13}{2}

2 x^{2} + 2 y^{2} - 14 x + 18 y = 7

x^{2} + y^{2} + 8 y = 3

x^{2} + y^{2} - 4 x - 6 y - 12 = 0

4 x^{2} + 12 x + 4 y^{2} + 16 y - 11 = 0

4 x^{2} + 4 y^{2} = 1

What is x^2+y^2+8x-9y=6 ?
The solution to x^2+y^2+8x-9y=6 is Circle with (a,b)=(-4, 9/2),r= 13/2