What is (x-5/3)^2+(y+7/3)^2=64 ?

The solution to (x-5/3)^2+(y+7/3)^2=64 is Circle with (a,b)=(5/3 ,-7/3),r=8

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(x-5/3)^2+(y+7/3)^2=64

(x - \frac{5}{3})^{2} + (y + \frac{7}{3})^{2} = 64

(a, b) = (\frac{5}{3}, - \frac{7}{3}), r = 8

Solution steps

(x - \frac{5}{3})^{2} + (y + \frac{7}{3})^{2} = 64

Rewrite

(x - \frac{5}{3})^{2} + (y + \frac{7}{3})^{2} = 64

in the form of the standard circle equation

(x - \frac{5}{3})^{2} + (y - (- \frac{7}{3}))^{2} = 8^{2}

Therefore the circle properties are:

(a, b) = (\frac{5}{3}, - \frac{7}{3}), r = 8

x^{2} + y^{2} - 16 x + 4 y + 32 = 0

(x + 2)^{2} + (y - 4)^{2} = 9

x^{2} - 4 x + y^{2} + 6 y = 12

(x^{2} - 6 x) + (y^{2} + 10 y) + 18 = 0

(x + 6)^{2} + y^{2} = 25

What is (x-5/3)^2+(y+7/3)^2=64 ?
The solution to (x-5/3)^2+(y+7/3)^2=64 is Circle with (a,b)=(5/3 ,-7/3),r=8