What is (x-3)^2+(y-1)^2=9 ?

The solution to (x-3)^2+(y-1)^2=9 is Circle with (a,b)=(3,1),r=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x-3)^2+(y-1)^2=9

(x - 3)^{2} + (y - 1)^{2} = 9

(a, b) = (3, 1), r = 3

Solution steps

(x - 3)^{2} + (y - 1)^{2} = 9

Rewrite

(x - 3)^{2} + (y - 1)^{2} = 9

in the form of the standard circle equation

(x - 3)^{2} + (y - 1)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (3, 1), r = 3

x^{2} + y^{2} + 2 x - 8 y + 12 = 0

x^{2} + y^{2} - 2 x - 4 y - 8 = 0

9 x^{2} + 9 y^{2} + 42 x + 84 y = - 65

2 x^{2} + 2 y^{2} - 8 x - 12 y + 8 = 0

1 - x^{2} - y^{2} = 0

What is (x-3)^2+(y-1)^2=9 ?
The solution to (x-3)^2+(y-1)^2=9 is Circle with (a,b)=(3,1),r=3