What is (x+5)^2+(y+8)^2=81 ?

The solution to (x+5)^2+(y+8)^2=81 is Circle with (a,b)=(-5,-8),r=9

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(x+5)^2+(y+8)^2=81

(x + 5)^{2} + (y + 8)^{2} = 81

(a, b) = (- 5, - 8), r = 9

Solution steps

(x + 5)^{2} + (y + 8)^{2} = 81

Rewrite

(x + 5)^{2} + (y + 8)^{2} = 81

in the form of the standard circle equation

(x - (- 5))^{2} + (y - (- 8))^{2} = 9^{2}

Therefore the circle properties are:

(a, b) = (- 5, - 8), r = 9

2 x^{2} + 2 y^{2} = 16

(x - 4)^{2} + (y - 1)^{2} = 25

x^{2} + y^{2} - 10 x + 8 y + 32 = 0

(x + 1)^{2} + (y - 13)^{2} = 4

(x + 4)^{2} + y^{2} = 49

What is (x+5)^2+(y+8)^2=81 ?
The solution to (x+5)^2+(y+8)^2=81 is Circle with (a,b)=(-5,-8),r=9