What is (x+9)^2+(y-4)^2=25 ?

The solution to (x+9)^2+(y-4)^2=25 is Circle with (a,b)=(-9,4),r=5

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(x+9)^2+(y-4)^2=25

(x + 9)^{2} + (y - 4)^{2} = 25

(a, b) = (- 9, 4), r = 5

Solution steps

(x + 9)^{2} + (y - 4)^{2} = 25

Rewrite

(x + 9)^{2} + (y - 4)^{2} = 25

in the form of the standard circle equation

(x - (- 9))^{2} + (y - 4)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 9, 4), r = 5

(x - 1)^{2} + (y + 2)^{2} = 36

(x - 0)^{2} + (y - 0)^{2} = 3^{2}

(x + 5)^{2} + y^{2} = 4

(x + 2)^{2} + (y + 4)^{2} = 4

(x + 40)^{2} + y^{2} = 30

What is (x+9)^2+(y-4)^2=25 ?
The solution to (x+9)^2+(y-4)^2=25 is Circle with (a,b)=(-9,4),r=5