What is 9x^2+9y^2+12x-6y+4=0 ?

The solution to 9x^2+9y^2+12x-6y+4=0 is Circle with (a,b)=(-2/3 , 1/3),r= 1/3

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9x^2+9y^2+12x-6y+4=0

9 x^{2} + 9 y^{2} + 12 x - 6 y + 4 = 0

(a, b) = (- \frac{2}{3}, \frac{1}{3}), r = \frac{1}{3}

Solution steps

9 x^{2} + 9 y^{2} + 12 x - 6 y + 4 = 0

Rewrite

9 x^{2} + 9 y^{2} + 12 x - 6 y + 4 = 0

in the form of the standard circle equation

(x - (- \frac{2}{3}))^{2} + (y - \frac{1}{3})^{2} = (\frac{1}{3})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{2}{3}, \frac{1}{3}), r = \frac{1}{3}

4 x^{2} + 4 y^{2} - 4 x - 12 y + 1 = 0

x^{2} + 4 x + y^{2} - 6 y - 3 = 0

(x + 6)^{2} + (y + 2)^{2} = 40

x^{2} + y^{2} = 289

x^{2} + y^{2} - 12 x - 8 y + 3 = 0

What is 9x^2+9y^2+12x-6y+4=0 ?
The solution to 9x^2+9y^2+12x-6y+4=0 is Circle with (a,b)=(-2/3 , 1/3),r= 1/3