What is (x+4)^2+(y+4)^2=9 ?

The solution to (x+4)^2+(y+4)^2=9 is Circle with (a,b)=(-4,-4),r=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x+4)^2+(y+4)^2=9

(x + 4)^{2} + (y + 4)^{2} = 9

(a, b) = (- 4, - 4), r = 3

Solution steps

(x + 4)^{2} + (y + 4)^{2} = 9

Rewrite

(x + 4)^{2} + (y + 4)^{2} = 9

in the form of the standard circle equation

(x - (- 4))^{2} + (y - (- 4))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- 4, - 4), r = 3

x^{2} + y^{2} + 2 x + 6 y = 0

x^{2} - 4 x + y^{2} + 6 y + 12 = 0

50 = 30 - 13 x + 5 y + \frac{x ^{2}}{2} + \frac{y ^{2}}{2}

x^{2} + y^{2} = 10 - x^{2} - y^{2}

x^{2} + y^{2} - 12 y = - 32

What is (x+4)^2+(y+4)^2=9 ?
The solution to (x+4)^2+(y+4)^2=9 is Circle with (a,b)=(-4,-4),r=3