What is (x-7)^2+(y+7)^2=64 ?

The solution to (x-7)^2+(y+7)^2=64 is Circle with (a,b)=(7,-7),r=8

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(x-7)^2+(y+7)^2=64

(x - 7)^{2} + (y + 7)^{2} = 64

(a, b) = (7, - 7), r = 8

Solution steps

(x - 7)^{2} + (y + 7)^{2} = 64

Rewrite

(x - 7)^{2} + (y + 7)^{2} = 64

in the form of the standard circle equation

(x - 7)^{2} + (y - (- 7))^{2} = 8^{2}

Therefore the circle properties are:

(a, b) = (7, - 7), r = 8

(x - 8)^{2} + (y + 5)^{2} = 4

x^{2} + (y - 4)^{2} = \frac{25}{9}

x^{2} + y^{2} = \frac{9}{4}

x^{2} + y^{2} + 12 x - 2 y = - 1

(x - 0)^{2} + (y - 0)^{2} = 5^{2}

What is (x-7)^2+(y+7)^2=64 ?
The solution to (x-7)^2+(y+7)^2=64 is Circle with (a,b)=(7,-7),r=8