What is (x-6)^2+(y-4)^2=64 ?

The solution to (x-6)^2+(y-4)^2=64 is Circle with (a,b)=(6,4),r=8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x-6)^2+(y-4)^2=64

(x - 6)^{2} + (y - 4)^{2} = 64

(a, b) = (6, 4), r = 8

Solution steps

(x - 6)^{2} + (y - 4)^{2} = 64

Rewrite

(x - 6)^{2} + (y - 4)^{2} = 64

in the form of the standard circle equation

(x - 6)^{2} + (y - 4)^{2} = 8^{2}

Therefore the circle properties are:

(a, b) = (6, 4), r = 8

x^{2} + y^{2} - 12 x + 6 y + 36 = 0

4 y^{2} + 4 x^{2} - 24 x + 35 = 0

x^{2} + y^{2} + 10 x + 14 y = - 70

x^{2} + y^{2} - 6 x - 4 y - 15 = 0

y^{2} = 7 - x^{2}

What is (x-6)^2+(y-4)^2=64 ?
The solution to (x-6)^2+(y-4)^2=64 is Circle with (a,b)=(6,4),r=8