What is x^2-6x+y^2-8y=39 ?

The solution to x^2-6x+y^2-8y=39 is Circle with (a,b)=(3,4),r=8

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x^2-6x+y^2-8y=39

x^{2} - 6 x + y^{2} - 8 y = 39

(a, b) = (3, 4), r = 8

Solution steps

x^{2} - 6 x + y^{2} - 8 y = 39

Rewrite

x^{2} - 6 x + y^{2} - 8 y = 39

in the form of the standard circle equation

(x - 3)^{2} + (y - 4)^{2} = 8^{2}

Therefore the circle properties are:

(a, b) = (3, 4), r = 8

x^{2} + (y + 2)^{2} = 49

X^{2} + Y^{2} = 4

(x - 1)^{2} + (y + 2)^{2} = 49

(x - \frac{5}{2})^{2} + (y + 2)^{2} = \frac{225}{4}

x^{2} + y^{2} + 6 x + 6 y + 9 = 0

What is x^2-6x+y^2-8y=39 ?
The solution to x^2-6x+y^2-8y=39 is Circle with (a,b)=(3,4),r=8