What is 2x^2+32x+2y^2-12=-128 ?

The solution to 2x^2+32x+2y^2-12=-128 is Circle with (a,b)=(-8,0),r=sqrt(6)

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2x^2+32x+2y^2-12=-128

2 x^{2} + 32 x + 2 y^{2} - 12 = - 128

(a, b) = (- 8, 0), r = 6

Solution steps

2 x^{2} + 32 x + 2 y^{2} - 12 = - 128

Rewrite

2 x^{2} + 32 x + 2 y^{2} - 12 = - 128

in the form of the standard circle equation

(x - (- 8))^{2} + (y - 0)^{2} = (6)^{2}

Therefore the circle properties are:

(a, b) = (- 8, 0), r = 6

(x - 5)^{2} + (y + 1)^{2} = 16

x^{2} + y^{2} - 2 x + 3 y - 10 = 0

a^{2} + b^{2} = 100

x^{2} + y^{2} - 6 x + 4 y = 12

x^{2} + y^{2} - 8 x - 10 y + 5 = 0

What is 2x^2+32x+2y^2-12=-128 ?
The solution to 2x^2+32x+2y^2-12=-128 is Circle with (a,b)=(-8,0),r=sqrt(6)