What is x^2+y^2+12x+16y+75=0 ?

The solution to x^2+y^2+12x+16y+75=0 is Circle with (a,b)=(-6,-8),r=5

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x^2+y^2+12x+16y+75=0

x^{2} + y^{2} + 12 x + 16 y + 75 = 0

(a, b) = (- 6, - 8), r = 5

Solution steps

x^{2} + y^{2} + 12 x + 16 y + 75 = 0

Rewrite

x^{2} + y^{2} + 12 x + 16 y + 75 = 0

in the form of the standard circle equation

(x - (- 6))^{2} + (y - (- 8))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 6, - 8), r = 5

x^{2} + y^{2} + 2 x + 4 y - 4091 = 0

(x + 1)^{2} + (y - 5)^{2} = 25

(x - 4)^{2} + (y - 2)^{2} = 16

x^{2} + y^{2} + 2 x - 4 y - 20 = 0

(x - 10)^{2} + (y + 4)^{2} = 25

What is x^2+y^2+12x+16y+75=0 ?
The solution to x^2+y^2+12x+16y+75=0 is Circle with (a,b)=(-6,-8),r=5