What is (x-10)^2+(y+8)^2=36 ?

The solution to (x-10)^2+(y+8)^2=36 is Circle with (a,b)=(10,-8),r=6

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(x-10)^2+(y+8)^2=36

(x - 10)^{2} + (y + 8)^{2} = 36

(a, b) = (10, - 8), r = 6

Solution steps

(x - 10)^{2} + (y + 8)^{2} = 36

Rewrite

(x - 10)^{2} + (y + 8)^{2} = 36

in the form of the standard circle equation

(x - 10)^{2} + (y - (- 8))^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (10, - 8), r = 6

x^{2} + y^{2} - 4 > 0

y^{2} + x^{2} = 10

(x - 6)^{2} + (y - 2)^{2} = 9

(x - 4)^{2} + (y + 3)^{2} = 9

(x - 6)^{2} + (y - 4)^{2} = 100

What is (x-10)^2+(y+8)^2=36 ?
The solution to (x-10)^2+(y+8)^2=36 is Circle with (a,b)=(10,-8),r=6