What is x^2+y^2-2y=3 ?

The solution to x^2+y^2-2y=3 is Circle with (a,b)=(0,1),r=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2+y^2-2y=3

x^{2} + y^{2} - 2 y = 3

(a, b) = (0, 1), r = 2

Solution steps

x^{2} + y^{2} - 2 y = 3

Rewrite

x^{2} + y^{2} - 2 y = 3

in the form of the standard circle equation

(x - 0)^{2} + (y - 1)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (0, 1), r = 2

x^{2} + y^{2} - 10 x - 10 y + 46 = 0

x^{2} + y^{2} - 16 y - 36 = 0

3 x^{2} + 3 y^{2} - 24 x + 6 y - 24 = 0

x^{2} + y^{2} + 2 x - 4 y + 4 = 0

(x + 3)^{2} + (y - 5)^{2} = 4

What is x^2+y^2-2y=3 ?
The solution to x^2+y^2-2y=3 is Circle with (a,b)=(0,1),r=2