What is 9x^2+9y^2-36x+6y+34=0 ?

The solution to 9x^2+9y^2-36x+6y+34=0 is Circle with (a,b)=(2,-1/3),r=sqrt(1/3)

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9x^2+9y^2-36x+6y+34=0

9 x^{2} + 9 y^{2} - 36 x + 6 y + 34 = 0

(a, b) = (2, - \frac{1}{3}), r = \frac{1}{3}

Solution steps

9 x^{2} + 9 y^{2} - 36 x + 6 y + 34 = 0

Rewrite

9 x^{2} + 9 y^{2} - 36 x + 6 y + 34 = 0

in the form of the standard circle equation

(x - 2)^{2} + (y - (- \frac{1}{3}))^{2} = (\frac{1}{3})^{2}

Therefore the circle properties are:

(a, b) = (2, - \frac{1}{3}), r = \frac{1}{3}

2 x - 3 x^{2} - 3 y^{2} = - 1

x^{2} + y^{2} - 8 x - 12 y + 43 = 0

(x - 3)^{2} + (y - 4)^{2} = 10

(x + 6)^{2} + (y - 3)^{2} = 16

(x + 55)^{2} + (y - 11.5)^{2} = 121

What is 9x^2+9y^2-36x+6y+34=0 ?
The solution to 9x^2+9y^2-36x+6y+34=0 is Circle with (a,b)=(2,-1/3),r=sqrt(1/3)