What is 3x^2+3y^2=12 ?

The solution to 3x^2+3y^2=12 is Circle with (a,b)=(0,0),r=2

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3x^2+3y^2=12

3 x^{2} + 3 y^{2} = 12

(a, b) = (0, 0), r = 2

Solution steps

3 x^{2} + 3 y^{2} = 12

Rewrite

3 x^{2} + 3 y^{2} = 12

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 2

x^{2} + y^{2} + 6 x - 8 y + 24 = 0

(x - 6)^{2} + (y + 3)^{2} = 10

(x + 4)^{2} + (y - 3)^{2} = 36

x^{2} + y^{2} - 14 x - 12 y + 76 = 0

\frac{( x - 3 ) ^{2}}{4} + \frac{( y + 2 ) ^{2}}{4} = 4

What is 3x^2+3y^2=12 ?
The solution to 3x^2+3y^2=12 is Circle with (a,b)=(0,0),r=2