What is x^2+(y+3)^2=25 ?

The solution to x^2+(y+3)^2=25 is Circle with (a,b)=(0,-3),r=5

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x^2+(y+3)^2=25

x^{2} + (y + 3)^{2} = 25

(a, b) = (0, - 3), r = 5

Solution steps

x^{2} + (y + 3)^{2} = 25

Rewrite

x^{2} + (y + 3)^{2} = 25

in the form of the standard circle equation

(x - 0)^{2} + (y - (- 3))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (0, - 3), r = 5

x^{2} + y^{2} + 4 y + 3 = 0

(x + 4)^{2} + (y - 2)^{2} = 16

(x - 2)^{2} + (y + 1)^{2} = 3

x^{2} + y^{2} - 10 x + 6 y - 15 = 0

4 (x - 5)^{2} + 4 y^{2} = 64

What is x^2+(y+3)^2=25 ?
The solution to x^2+(y+3)^2=25 is Circle with (a,b)=(0,-3),r=5