What is x^2+y^2+14x-2=-1 ?

The solution to x^2+y^2+14x-2=-1 is Circle with (a,b)=(-7,0),r=5sqrt(2)

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x^2+y^2+14x-2=-1

x^{2} + y^{2} + 14 x - 2 = - 1

(a, b) = (- 7, 0), r = 52

Solution steps

x^{2} + y^{2} + 14 x - 2 = - 1

Rewrite

x^{2} + y^{2} + 14 x - 2 = - 1

in the form of the standard circle equation

(x - (- 7))^{2} + (y - 0)^{2} = (52)^{2}

Therefore the circle properties are:

(a, b) = (- 7, 0), r = 52

(x - 5)^{2} + (y + 3)^{2} = 25

4 x^{2} + 4 y^{2} - 20 x + 40 y + 5 = 0

x^{2} + y^{2} - 6 x - 8 y + 16 = 0

x^{2} + y^{2} + 10 x - 18 y + 70 = 0

x^{2} + y^{2} - 2 x - 80 = 0

What is x^2+y^2+14x-2=-1 ?
The solution to x^2+y^2+14x-2=-1 is Circle with (a,b)=(-7,0),r=5sqrt(2)