What is (x-1)^2+(y-2)^2=5^2 ?

The solution to (x-1)^2+(y-2)^2=5^2 is Circle with (a,b)=(1,2),r=5

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(x-1)^2+(y-2)^2=5^2

(x - 1)^{2} + (y - 2)^{2} = 5^{2}

(a, b) = (1, 2), r = 5

Solution steps

(x - 1)^{2} + (y - 2)^{2} = 5^{2}

Rewrite

(x - 1)^{2} + (y - 2)^{2} = 5^{2}

in the form of the standard circle equation

(x - 1)^{2} + (y - 2)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (1, 2), r = 5

x^{2} + y^{2} - 4 x + 18 y + 4 = 0

(x - \frac{3}{2})^{2} + (y - 7)^{2} = 5^{2}

(x - 3.5)^{2} + (y - 3)^{2} < 4.1

x^{2} + (y + 14)^{2} = 25

x^{2} + y^{2} - 12 x + 12 y + 36 = 0

What is (x-1)^2+(y-2)^2=5^2 ?
The solution to (x-1)^2+(y-2)^2=5^2 is Circle with (a,b)=(1,2),r=5