What is x^2+y^2+5x+4y=46 ?

The solution to x^2+y^2+5x+4y=46 is Circle with (a,b)=(-5/2 ,-2),r= 15/2

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x^2+y^2+5x+4y=46

x^{2} + y^{2} + 5 x + 4 y = 46

(a, b) = (- \frac{5}{2}, - 2), r = \frac{15}{2}

Solution steps

x^{2} + y^{2} + 5 x + 4 y = 46

Rewrite

x^{2} + y^{2} + 5 x + 4 y = 46

in the form of the standard circle equation

(x - (- \frac{5}{2}))^{2} + (y - (- 2))^{2} = (\frac{15}{2})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{5}{2}, - 2), r = \frac{15}{2}

9 x^{2} + 9 y^{2} - 6 x + 12 y + 4 = 0

x^{2} + y^{2} + 10 x - 16 y - 55 = 0

(x + 8)^{2} + (y + 5)^{2} = 256

x^{2} - 16 x + y^{2} - 36 = 0

(x - \frac{7}{4})^{2} + (y - \frac{3}{4})^{2} = \frac{169}{16}

What is x^2+y^2+5x+4y=46 ?
The solution to x^2+y^2+5x+4y=46 is Circle with (a,b)=(-5/2 ,-2),r= 15/2