What is (x-3)^2+(y-2)^2=5 ?

The solution to (x-3)^2+(y-2)^2=5 is Circle with (a,b)=(3,2),r=sqrt(5)

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(x-3)^2+(y-2)^2=5

(x - 3)^{2} + (y - 2)^{2} = 5

(a, b) = (3, 2), r = 5

Solution steps

(x - 3)^{2} + (y - 2)^{2} = 5

Rewrite

(x - 3)^{2} + (y - 2)^{2} = 5

in the form of the standard circle equation

(x - 3)^{2} + (y - 2)^{2} = (5)^{2}

Therefore the circle properties are:

(a, b) = (3, 2), r = 5

(x - 3)^{2} + (y - 2)^{2} = 2

x^{2} + y^{2} - 4 x - 12 y - 23 = 0

x^{2} + y^{2} + 8 y - 33 = 0

(x + 2)^{2} + (y + 4)^{2} = 40

x^{2} + y^{2} - 10 x + 6 y - 2 = 0

What is (x-3)^2+(y-2)^2=5 ?
The solution to (x-3)^2+(y-2)^2=5 is Circle with (a,b)=(3,2),r=sqrt(5)