What is 2x^2-20x+2y^2+12y=-18 ?

The solution to 2x^2-20x+2y^2+12y=-18 is Circle with (a,b)=(5,-3),r=5

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2x^2-20x+2y^2+12y=-18

2 x^{2} - 20 x + 2 y^{2} + 12 y = - 18

(a, b) = (5, - 3), r = 5

Solution steps

2 x^{2} - 20 x + 2 y^{2} + 12 y = - 18

Rewrite

2 x^{2} - 20 x + 2 y^{2} + 12 y = - 18

in the form of the standard circle equation

(x - 5)^{2} + (y - (- 3))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (5, - 3), r = 5

(x - 5)^{2} + y^{2} - 8 y = 0

x^{2} + y^{2} - 8 x + 4 y = 0

(x + 4)^{2} + (y - 4 \frac{1}{2})^{2} = 42 \frac{1}{4}

x^{2} + y^{2} + 8 x - 2 y + 13 = 0

x^{2} + y^{2} - 6 y + 8 = 0

What is 2x^2-20x+2y^2+12y=-18 ?
The solution to 2x^2-20x+2y^2+12y=-18 is Circle with (a,b)=(5,-3),r=5