What is 2x^2+2y^2+44x+28y=52 ?

The solution to 2x^2+2y^2+44x+28y=52 is Circle with (a,b)=(-11,-7),r=14

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2x^2+2y^2+44x+28y=52

2 x^{2} + 2 y^{2} + 44 x + 28 y = 52

(a, b) = (- 11, - 7), r = 14

Solution steps

2 x^{2} + 2 y^{2} + 44 x + 28 y = 52

Rewrite

2 x^{2} + 2 y^{2} + 44 x + 28 y = 52

in the form of the standard circle equation

(x - (- 11))^{2} + (y - (- 7))^{2} = 1 4^{2}

Therefore the circle properties are:

(a, b) = (- 11, - 7), r = 14

x^{2} + (y - 8)^{2} = 5

(x - 6)^{2} + (y - 4)^{2} = 5^{2}

25.314 4^{2} = (27.2 - x)^{2} + (27.2 - y)^{2}

x^{2} - 4 x + y^{2} + 6 y + 4 = 0

(x + 1)^{2} + (y - 4)^{2} = 9

What is 2x^2+2y^2+44x+28y=52 ?
The solution to 2x^2+2y^2+44x+28y=52 is Circle with (a,b)=(-11,-7),r=14