What is x^2+10x+y^2-12y=3 ?

The solution to x^2+10x+y^2-12y=3 is Circle with (a,b)=(-5,6),r=8

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x^2+10x+y^2-12y=3

x^{2} + 10 x + y^{2} - 12 y = 3

(a, b) = (- 5, 6), r = 8

Solution steps

x^{2} + 10 x + y^{2} - 12 y = 3

Rewrite

x^{2} + 10 x + y^{2} - 12 y = 3

in the form of the standard circle equation

(x - (- 5))^{2} + (y - 6)^{2} = 8^{2}

Therefore the circle properties are:

(a, b) = (- 5, 6), r = 8

x^{2} + y^{2} - 22 y - 5 = 0

x^{2} + y^{2} + 6 x + 8 y - 75 = 0

\frac{1}{2} x^{2} + \frac{1}{2} y^{2} = 16

(x - 5)^{2} + y^{2} = 38

(x - 4)^{2} + (y - 2)^{2} = 4

What is x^2+10x+y^2-12y=3 ?
The solution to x^2+10x+y^2-12y=3 is Circle with (a,b)=(-5,6),r=8