What is 4x^2+4y^2-24x-12y+29=0 ?

The solution to 4x^2+4y^2-24x-12y+29=0 is Circle with (a,b)=(3, 3/2),r=2

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4x^2+4y^2-24x-12y+29=0

4 x^{2} + 4 y^{2} - 24 x - 12 y + 29 = 0

(a, b) = (3, \frac{3}{2}), r = 2

Solution steps

4 x^{2} + 4 y^{2} - 24 x - 12 y + 29 = 0

Rewrite

4 x^{2} + 4 y^{2} - 24 x - 12 y + 29 = 0

in the form of the standard circle equation

(x - 3)^{2} + (y - \frac{3}{2})^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (3, \frac{3}{2}), r = 2

(x)^{2} + (y)^{2} = 49

y^{2} + z^{2} = 25

x^{2} - 2 x + y^{2} + 4 y - 4 = 0

(x - 5)^{2} + (y - 3)^{2} = 81

x^{2} + 8 x + y^{2} - 9 y = 6

What is 4x^2+4y^2-24x-12y+29=0 ?
The solution to 4x^2+4y^2-24x-12y+29=0 is Circle with (a,b)=(3, 3/2),r=2