What is x^2+y^2-22x-12y+150=0 ?

The solution to x^2+y^2-22x-12y+150=0 is Circle with (a,b)=(11,6),r=sqrt(7)

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x^2+y^2-22x-12y+150=0

x^{2} + y^{2} - 22 x - 12 y + 150 = 0

(a, b) = (11, 6), r = 7

Solution steps

x^{2} + y^{2} - 22 x - 12 y + 150 = 0

Rewrite

x^{2} + y^{2} - 22 x - 12 y + 150 = 0

in the form of the standard circle equation

(x - 11)^{2} + (y - 6)^{2} = (7)^{2}

Therefore the circle properties are:

(a, b) = (11, 6), r = 7

x^{2} + y^{2} + 4 x - 6 y + 2 = 0

x^{2} + 8 y + y^{2} + 7 = 0

(x - 1)^{2} + (y - 4)^{2} = 4

x^{2} + 4 x + y^{2} + 8 y + 16 = 0

(x^{2} + (- 10) x + 25) + (y^{2} + 9 y + \frac{81}{4}) = - 1 + 25 + \frac{81}{4}

What is x^2+y^2-22x-12y+150=0 ?
The solution to x^2+y^2-22x-12y+150=0 is Circle with (a,b)=(11,6),r=sqrt(7)