What is x^2+6x+y^2-10y=135 ?

The solution to x^2+6x+y^2-10y=135 is Circle with (a,b)=(-3,5),r=13

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x^2+6x+y^2-10y=135

x^{2} + 6 x + y^{2} - 10 y = 135

(a, b) = (- 3, 5), r = 13

Solution steps

x^{2} + 6 x + y^{2} - 10 y = 135

Rewrite

x^{2} + 6 x + y^{2} - 10 y = 135

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 5)^{2} = 1 3^{2}

Therefore the circle properties are:

(a, b) = (- 3, 5), r = 13

z^{2} = 4 - y^{2}

1 = (x - 1)^{2} + (y + 4)^{2}

(x + 1)^{2} + (y - 5)^{2} = 20

x^{2} + y^{2} + 6 x - 8 y + 13 = 0

(x + 4)^{2} + (y - 5)^{2} = 4

What is x^2+6x+y^2-10y=135 ?
The solution to x^2+6x+y^2-10y=135 is Circle with (a,b)=(-3,5),r=13