What is x^2+(y-4)^2=49 ?

The solution to x^2+(y-4)^2=49 is Circle with (a,b)=(0,4),r=7

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x^2+(y-4)^2=49

x^{2} + (y - 4)^{2} = 49

(a, b) = (0, 4), r = 7

Solution steps

x^{2} + (y - 4)^{2} = 49

Rewrite

x^{2} + (y - 4)^{2} = 49

in the form of the standard circle equation

(x - 0)^{2} + (y - 4)^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (0, 4), r = 7

x^{2} + y^{2} - x - 10 y + 5 = 0

x^{2} + y^{2} + 5 x - 10 y - 5 = 0

a^{2} - 28 + b^{2} = 7

\frac{( x - 5 ) ^{2}}{4} + \frac{( y + 3 ) ^{2}}{4} = 1

(x - 6)^{2} + (y - 4)^{2} = 8^{2}

What is x^2+(y-4)^2=49 ?
The solution to x^2+(y-4)^2=49 is Circle with (a,b)=(0,4),r=7