What is {x-(-3)}^2+{y-(-4)}^2=1 ?

The solution to {x-(-3)}^2+{y-(-4)}^2=1 is Circle with (a,b)=(-3,-4),r=1

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{x-(-3)}^2+{y-(-4)}^2=1

{x - (- 3)}^{2} + {y - (- 4)}^{2} = 1

(a, b) = (- 3, - 4), r = 1

Solution steps

{x - (- 3)}^{2} + {y - (- 4)}^{2} = 1

Rewrite

{x - (- 3)}^{2} + {y - (- 4)}^{2} = 1

in the form of the standard circle equation

(x - (- 3))^{2} + (y - (- 4))^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (- 3, - 4), r = 1

(x - 5)^{2} + (y + 2)^{2} = 7.5

x^{2} + (y - 7.5)^{2} = \frac{9}{49}

x^{2} + y^{2} - 2 x + 8 y = 0

x^{2} + y^{2} + 10 x - 4 y - 8 = 0

x^{2} + y^{2} - 4 x - 12 y + 24 = 0

What is {x-(-3)}^2+{y-(-4)}^2=1 ?
The solution to {x-(-3)}^2+{y-(-4)}^2=1 is Circle with (a,b)=(-3,-4),r=1