What is (x+7/2)^2+(y-5/2)^2= 125/2 ?

The solution to (x+7/2)^2+(y-5/2)^2= 125/2 is Circle with (a,b)=(-7/2 , 5/2),r=sqrt(125/2)

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(x+7/2)^2+(y-5/2)^2= 125/2

(x + \frac{7}{2})^{2} + (y - \frac{5}{2})^{2} = \frac{125}{2}

(a, b) = (- \frac{7}{2}, \frac{5}{2}), r = \frac{125}{2}

Solution steps

(x + \frac{7}{2})^{2} + (y - \frac{5}{2})^{2} = \frac{125}{2}

Rewrite

(x + \frac{7}{2})^{2} + (y - \frac{5}{2})^{2} = \frac{125}{2}

in the form of the standard circle equation

(x - (- \frac{7}{2}))^{2} + (y - \frac{5}{2})^{2} = (\frac{125}{2})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{7}{2}, \frac{5}{2}), r = \frac{125}{2}

x^{2} + (y - 5)^{2} = 4

x^{2} + y^{2} - 6 x - 16 = 0

x^{2} + y^{2} + 40 x + 20 y + 400 = 0

x^{2} + y^{2} - 6 x - 8 y - 23 = 0

(x + 7)^{2} + (y - 1)^{2} = 49

What is (x+7/2)^2+(y-5/2)^2= 125/2 ?
The solution to (x+7/2)^2+(y-5/2)^2= 125/2 is Circle with (a,b)=(-7/2 , 5/2),r=sqrt(125/2)