What is 9x^2+9y^2-42x+94y+65=0 ?

The solution to 9x^2+9y^2-42x+94y+65=0 is Circle with (a,b)=(7/3 ,-47/9),r=(sqrt(2065))/9

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9x^2+9y^2-42x+94y+65=0

9 x^{2} + 9 y^{2} - 42 x + 94 y + 65 = 0

(a, b) = (\frac{7}{3}, - \frac{47}{9}), r = \frac{2065}{9}

Solution steps

9 x^{2} + 9 y^{2} - 42 x + 94 y + 65 = 0

Rewrite

9 x^{2} + 9 y^{2} - 42 x + 94 y + 65 = 0

in the form of the standard circle equation

(x - \frac{7}{3})^{2} + (y - (- \frac{47}{9}))^{2} = (\frac{2065}{9})^{2}

Therefore the circle properties are:

(a, b) = (\frac{7}{3}, - \frac{47}{9}), r = \frac{2065}{9}

x^{2} + (y - 8)^{2} = 64

(x - 2)^{2} + (y - 3)^{2} = 3

x^{2} - 4 x + y^{2} + 2 y - 4 = 0

(x - 2)^{2} + (y - 3)^{2} = 7

x^{2} + y^{2} - 4 = x + y - 2

What is 9x^2+9y^2-42x+94y+65=0 ?
The solution to 9x^2+9y^2-42x+94y+65=0 is Circle with (a,b)=(7/3 ,-47/9),r=(sqrt(2065))/9