What is (x-1)^2+(y-3)^2=49 ?

The solution to (x-1)^2+(y-3)^2=49 is Circle with (a,b)=(1,3),r=7

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(x-1)^2+(y-3)^2=49

(x - 1)^{2} + (y - 3)^{2} = 49

(a, b) = (1, 3), r = 7

Solution steps

(x - 1)^{2} + (y - 3)^{2} = 49

Rewrite

(x - 1)^{2} + (y - 3)^{2} = 49

in the form of the standard circle equation

(x - 1)^{2} + (y - 3)^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (1, 3), r = 7

(x + 1)^{2} + (y - 2)^{2} = 49

x^{2} + y^{2} - 6 x + 6 y + 10 = 0

x^{2} + y^{2} - 2 x - 6 y + 9 = 0

4 x^{2} + 4 y^{2} + 32 y - 36 = 0

(x - 1)^{2} + (y - 3)^{2} = 16

What is (x-1)^2+(y-3)^2=49 ?
The solution to (x-1)^2+(y-3)^2=49 is Circle with (a,b)=(1,3),r=7