What is (x+5)^2+(y+6)^2= 2/3 ?

The solution to (x+5)^2+(y+6)^2= 2/3 is Circle with (a,b)=(-5,-6),r=sqrt(2/3)

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(x+5)^2+(y+6)^2= 2/3

(x + 5)^{2} + (y + 6)^{2} = \frac{2}{3}

(a, b) = (- 5, - 6), r = \frac{2}{3}

Solution steps

(x + 5)^{2} + (y + 6)^{2} = \frac{2}{3}

Rewrite

(x + 5)^{2} + (y + 6)^{2} = \frac{2}{3}

in the form of the standard circle equation

(x - (- 5))^{2} + (y - (- 6))^{2} = (\frac{2}{3})^{2}

Therefore the circle properties are:

(a, b) = (- 5, - 6), r = \frac{2}{3}

x^{2} + y^{2} = 36 - 3 x^{2} - 3 y^{2}

p^{2} + q^{2} = 16

(x - 4)^{2} + (y - 3)^{2} = 1

(x - 4)^{2} + (y - 3)^{2} = 9

(x - 4)^{2} + (y - 3)^{2} = 36

What is (x+5)^2+(y+6)^2= 2/3 ?
The solution to (x+5)^2+(y+6)^2= 2/3 is Circle with (a,b)=(-5,-6),r=sqrt(2/3)