What is 3x^2+3y^2-12x+15y=21 ?

The solution to 3x^2+3y^2-12x+15y=21 is Circle with (a,b)=(2,-5/2),r=(sqrt(69))/2

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3x^2+3y^2-12x+15y=21

3 x^{2} + 3 y^{2} - 12 x + 15 y = 21

(a, b) = (2, - \frac{5}{2}), r = \frac{69}{2}

Solution steps

3 x^{2} + 3 y^{2} - 12 x + 15 y = 21

Rewrite

3 x^{2} + 3 y^{2} - 12 x + 15 y = 21

in the form of the standard circle equation

(x - 2)^{2} + (y - (- \frac{5}{2}))^{2} = (\frac{69}{2})^{2}

Therefore the circle properties are:

(a, b) = (2, - \frac{5}{2}), r = \frac{69}{2}

(x - 4)^{2} + (y - 1)^{2} = 49

x^{2} + y^{2} - 32 x - 8 y + 264 = 0

(x - 2)^{2} + (y + 5)^{2} = 49

\frac{( x + 5 ) ^{2}}{\frac{9}{25}} + \frac{( y + 4 ) ^{2}}{\frac{9}{25}} = 1

x^{2} + y^{2} - 8 x + 14 y + 16 = 0

What is 3x^2+3y^2-12x+15y=21 ?
The solution to 3x^2+3y^2-12x+15y=21 is Circle with (a,b)=(2,-5/2),r=(sqrt(69))/2