What is 5=(sqrt((x+1)^2+(y-(-5))^2))^2 ?

The solution to 5=(sqrt((x+1)^2+(y-(-5))^2))^2 is Circle with (a,b)=(-1,-5),r=sqrt(5)

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5=(sqrt((x+1)^2+(y-(-5))^2))^2

5 = ((x + 1)^{2} + (y - (- 5))^{2})^{2}

(a, b) = (- 1, - 5), r = 5

Solution steps

5 = ((x + 1)^{2} + (y - (- 5))^{2})^{2}

Rewrite

5 = (x + 1)^{2} + (y - (- 5))^{2}^{2}

in the form of the standard circle equation

(x - (- 1))^{2} + (y - (- 5))^{2} = (5)^{2}

Therefore the circle properties are:

(a, b) = (- 1, - 5), r = 5

x^{(2)} - 6 x + y^{(2)} + 4 y = 3

x^{2} + y^{2} - 6 x + 12 y + 20 = 0

x^{2} + 8 x + y^{2} - 2 y + 17 = 4 x^{2} - 24 x + 4 y^{2} - 16 y + 52

(x - 6)^{2} + (y - 3)^{2} = 324

(x + 2)^{2} + (y - \frac{3}{7})^{2} = \frac{16}{9}

What is 5=(sqrt((x+1)^2+(y-(-5))^2))^2 ?
The solution to 5=(sqrt((x+1)^2+(y-(-5))^2))^2 is Circle with (a,b)=(-1,-5),r=sqrt(5)