What is (x-5)^2+(y-5)^2=100 ?

The solution to (x-5)^2+(y-5)^2=100 is Circle with (a,b)=(5,5),r=10

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(x-5)^2+(y-5)^2=100

(x - 5)^{2} + (y - 5)^{2} = 100

(a, b) = (5, 5), r = 10

Solution steps

(x - 5)^{2} + (y - 5)^{2} = 100

Rewrite

(x - 5)^{2} + (y - 5)^{2} = 100

in the form of the standard circle equation

(x - 5)^{2} + (y - 5)^{2} = 1 0^{2}

Therefore the circle properties are:

(a, b) = (5, 5), r = 10

x^{2} + y^{2} + \frac{20}{17} x - \frac{72}{17} y - \frac{912}{17} = 0

x^{2} + y^{2} + 4 x - 4 y - 32 = 0

72 = x^{2} + 6 x + 9 + y^{2} - 4 y + 4

(x + 6)^{2} + (y - 4)^{2} = 16

x^{2} + y^{2} + 2 x + 16 y + 1 = 0

What is (x-5)^2+(y-5)^2=100 ?
The solution to (x-5)^2+(y-5)^2=100 is Circle with (a,b)=(5,5),r=10