What is y^2=-x^2-2x ?

The solution to y^2=-x^2-2x is Circle with (a,b)=(-1,0),r=1

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y^2=-x^2-2x

y^{2} = - x^{2} - 2 x

(a, b) = (- 1, 0), r = 1

Solution steps

y^{2} = - x^{2} - 2 x

Rewrite

y^{2} = - x^{2} - 2 x

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 0)^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (- 1, 0), r = 1

x^{2} + y^{2} - 4 x + 2 y = - 4

x^{2} + y^{2} = (22)^{2}

(x - 1)^{2} + (y - 4)^{2} = 81

(x + \frac{1}{7})^{2} + (y - \frac{3}{5})^{2} = \frac{25}{9}

(x - 4)^{2} + (y + 12)^{2} = 1 7^{2}

What is y^2=-x^2-2x ?
The solution to y^2=-x^2-2x is Circle with (a,b)=(-1,0),r=1