What is 4x-x^2-y^2-6y-2>0 ?

The solution to 4x-x^2-y^2-6y-2>0 is Circle with (a,b)=(2,-3),r=sqrt(11)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4x-x^2-y^2-6y-2>0

4 x - x^{2} - y^{2} - 6 y - 2 > 0

(a, b) = (2, - 3), r = 11

Solution steps

4 x - x^{2} - y^{2} - 6 y - 2 > 0

Rewrite

4 x - x^{2} - y^{2} - 6 y - 2 > 0

in the form of the standard circle equation

(x - 2)^{2} + (y - (- 3))^{2} = (11)^{2}

Therefore the circle properties are:

(a, b) = (2, - 3), r = 11

(x - \frac{2}{3})^{2} + (y - \frac{4}{3})^{2} = \frac{20}{9}

(x^{2} - 2 x) + (y^{2} - 2 y) = 7

x^{2} + y^{2} - 1 = x

3 x^{2} - 12 x + 3 y^{2} - 6 y - 12 = 0

x^{2} + y^{2} + 4 x + 10 y + 25 = 0

What is 4x-x^2-y^2-6y-2>0 ?
The solution to 4x-x^2-y^2-6y-2>0 is Circle with (a,b)=(2,-3),r=sqrt(11)