What is 16x^2+16y^2+96x+40y=315 ?

The solution to 16x^2+16y^2+96x+40y=315 is Circle with (a,b)=(-3,-5/4),r= 11/2

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16x^2+16y^2+96x+40y=315

16 x^{2} + 16 y^{2} + 96 x + 40 y = 315

(a, b) = (- 3, - \frac{5}{4}), r = \frac{11}{2}

Solution steps

16 x^{2} + 16 y^{2} + 96 x + 40 y = 315

Rewrite

16 x^{2} + 16 y^{2} + 96 x + 40 y = 315

in the form of the standard circle equation

(x - (- 3))^{2} + (y - (- \frac{5}{4}))^{2} = (\frac{11}{2})^{2}

Therefore the circle properties are:

(a, b) = (- 3, - \frac{5}{4}), r = \frac{11}{2}

(x - 4)^{2} + (y - 5)^{2} = 25

x^{2} + y^{2} + 2 y = 3

x^{2} + y^{2} + 2 y = 8

(x - 4)^{2} + (y - 5)^{2} = 36

(x + 1)^{2} + (y - 1)^{2} = 9

What is 16x^2+16y^2+96x+40y=315 ?
The solution to 16x^2+16y^2+96x+40y=315 is Circle with (a,b)=(-3,-5/4),r= 11/2