What is (x+3/2)^2+(y-1/2)^2=25 ?

The solution to (x+3/2)^2+(y-1/2)^2=25 is Circle with (a,b)=(-3/2 , 1/2),r=5

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(x+3/2)^2+(y-1/2)^2=25

(x + \frac{3}{2})^{2} + (y - \frac{1}{2})^{2} = 25

(a, b) = (- \frac{3}{2}, \frac{1}{2}), r = 5

Solution steps

(x + \frac{3}{2})^{2} + (y - \frac{1}{2})^{2} = 25

Rewrite

(x + \frac{3}{2})^{2} + (y - \frac{1}{2})^{2} = 25

in the form of the standard circle equation

(x - (- \frac{3}{2}))^{2} + (y - \frac{1}{2})^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- \frac{3}{2}, \frac{1}{2}), r = 5

x^{2} + y^{2} + 8 x - 2 y - 17 = 0

4 x^{2} - 4 x + 4 y^{2} - 20 = 0

x^{2} + (y - 4)^{2} = 36

3 x^{2} + 3 y^{2} - 18 - 12 y = 108

x^{2} + y^{2} - 12 x + 4 y = - 2

What is (x+3/2)^2+(y-1/2)^2=25 ?
The solution to (x+3/2)^2+(y-1/2)^2=25 is Circle with (a,b)=(-3/2 , 1/2),r=5