What is (x+1)^2+(y+2)^2= 17/32 ?

The solution to (x+1)^2+(y+2)^2= 17/32 is Circle with (a,b)=(-1,-2),r=sqrt(17/32)

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(x+1)^2+(y+2)^2= 17/32

(x + 1)^{2} + (y + 2)^{2} = \frac{17}{32}

(a, b) = (- 1, - 2), r = \frac{17}{32}

Solution steps

(x + 1)^{2} + (y + 2)^{2} = \frac{17}{32}

Rewrite

(x + 1)^{2} + (y + 2)^{2} = \frac{17}{32}

in the form of the standard circle equation

(x - (- 1))^{2} + (y - (- 2))^{2} = (\frac{17}{32})^{2}

Therefore the circle properties are:

(a, b) = (- 1, - 2), r = \frac{17}{32}

4 x^{2} + 4 y^{2} + 0^{2} = 16

x^{2} + y^{2} - x - 3 y - 2 = 0

(x + 3)^{2} + (y - 5)^{2} = 4^{2}

x^{2} + 5 x + y^{2} - 7 y + \frac{247}{16} = 0

(x - 5)^{(2)} + (y + 7)^{(2)} = 50

What is (x+1)^2+(y+2)^2= 17/32 ?
The solution to (x+1)^2+(y+2)^2= 17/32 is Circle with (a,b)=(-1,-2),r=sqrt(17/32)