What is (x^2)/4+(y^2)/4 =25 ?

The solution to (x^2)/4+(y^2)/4 =25 is Circle with (a,b)=(0,0),r=10

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(x^2)/4+(y^2)/4 =25

\frac{x ^{2}}{4} + \frac{y ^{2}}{4} = 25

(a, b) = (0, 0), r = 10

Solution steps

\frac{x ^{2}}{4} + \frac{y ^{2}}{4} = 25

Rewrite

\frac{x ^{2}}{4} + \frac{y ^{2}}{4} = 25

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 1 0^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 10

x^{2} + y^{2} - 8 x - 2 y + 7 = 0

(x - (- 3))^{2} + (y - (- 2))^{2} = 8^{2}

(a + bi) \cdot (a - bi) = 1

x^{2} + y^{2} + 8 x + 2 y + 4 = 0

\frac{x ^{2} + y ^{2}}{2} = 1

What is (x^2)/4+(y^2)/4 =25 ?
The solution to (x^2)/4+(y^2)/4 =25 is Circle with (a,b)=(0,0),r=10