What is (y+2)^2=20-(x-4)^2 ?

The solution to (y+2)^2=20-(x-4)^2 is Circle with (a,b)=(4,-2),r=sqrt(20)

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(y+2)^2=20-(x-4)^2

(y + 2)^{2} = 20 - (x - 4)^{2}

(a, b) = (4, - 2), r = 20

Solution steps

(y + 2)^{2} = 20 - (x - 4)^{2}

Rewrite

(y + 2)^{2} = 20 - (x - 4)^{2}

in the form of the standard circle equation

(x - 4)^{2} + (y - (- 2))^{2} = (20)^{2}

Therefore the circle properties are:

(a, b) = (4, - 2), r = 20

(x - 2)^{2} + (y - 3)^{2} = 1

x^{2} + (y - 8)^{2} = 81

(x - 4)^{2} + (y - 4)^{2} = 9

(x - 4)^{2} + (y - 4)^{2} = 5

4 x^{2} + 4 y^{2} - 4 x + 12 y - 71 = 0

What is (y+2)^2=20-(x-4)^2 ?
The solution to (y+2)^2=20-(x-4)^2 is Circle with (a,b)=(4,-2),r=sqrt(20)