What is 2(-y+1)=(1/2 (-x-1))^2 ?

The solution to 2(-y+1)=(1/2 (-x-1))^2 is Parabola with (h,k)=(-1,0),p=-2

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2(-y+1)=(1/2 (-x-1))^2

2 (- y + 1) = (\frac{1}{2} (- x - 1))^{2}

(h, k) = (- 1, 0), p = - 2

Solution steps

2 (- y + 1) = (\frac{1}{2} (- x - 1))^{2}

Rewrite

2 (- y + 1) = (\frac{1}{2} (- x - 1))^{2}

in the standard form

4 (- 2) (y - 0) = (x - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (- 1, 0), p = - 2

3 x^{2} - y = 12

(x + 5)^{2} = - 4 (y + 1)

3 y^{2} + 6 x - y + 2 = 0

(x - 1)^{2} = 12 y

y^{2} + x = 3

What is 2(-y+1)=(1/2 (-x-1))^2 ?
The solution to 2(-y+1)=(1/2 (-x-1))^2 is Parabola with (h,k)=(-1,0),p=-2