What is (x-1/2)^2+(y-1/3)^2= 1/2 ?

The solution to (x-1/2)^2+(y-1/3)^2= 1/2 is Circle with (a,b)=(1/2 , 1/3),r=sqrt(1/2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x-1/2)^2+(y-1/3)^2= 1/2

(x - \frac{1}{2})^{2} + (y - \frac{1}{3})^{2} = \frac{1}{2}

(a, b) = (\frac{1}{2}, \frac{1}{3}), r = \frac{1}{2}

Solution steps

(x - \frac{1}{2})^{2} + (y - \frac{1}{3})^{2} = \frac{1}{2}

Rewrite

(x - \frac{1}{2})^{2} + (y - \frac{1}{3})^{2} = \frac{1}{2}

in the form of the standard circle equation

(x - \frac{1}{2})^{2} + (y - \frac{1}{3})^{2} = (\frac{1}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{1}{2}, \frac{1}{3}), r = \frac{1}{2}

x^{2} + y^{2} - 12 x - 16 y + 19 = 0

x^{2} + y^{2} + 20 x - 10 y = - 27

x^{2} + y^{2} + 2 x + 18 y = - 1

x^{(2)} + y^{(2)} + 2 x + 2 y - 7 = 0

2 x^{2} + 2 y^{2} = 72

What is (x-1/2)^2+(y-1/3)^2= 1/2 ?
The solution to (x-1/2)^2+(y-1/3)^2= 1/2 is Circle with (a,b)=(1/2 , 1/3),r=sqrt(1/2)