What is x^2+y^2+5x=(-1)/4-5y ?

The solution to x^2+y^2+5x=(-1)/4-5y is Circle with (a,b)=(-5/2 ,-5/2),r= 7/2

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x^2+y^2+5x=(-1)/4-5y

x^{2} + y^{2} + 5 x = \frac{- 1}{4} - 5 y

(a, b) = (- \frac{5}{2}, - \frac{5}{2}), r = \frac{7}{2}

Solution steps

x^{2} + y^{2} + 5 x = \frac{- 1}{4} - 5 y

Rewrite

x^{2} + y^{2} + 5 x = \frac{- 1}{4} - 5 y

in the form of the standard circle equation

(x - (- \frac{5}{2}))^{2} + (y - (- \frac{5}{2}))^{2} = (\frac{7}{2})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{5}{2}, - \frac{5}{2}), r = \frac{7}{2}

x^{2} + y^{2} - 6 x + 5 = 5

x^{2} + y^{2} - 6 x + 5 = 3

x^{2} + y^{2} - 5 x + \frac{1}{4} = 0

(x - 5)^{2} + (y + 3)^{2} = 51

x^{2} + y^{2} + 10 x + 15 = 0

What is x^2+y^2+5x=(-1)/4-5y ?
The solution to x^2+y^2+5x=(-1)/4-5y is Circle with (a,b)=(-5/2 ,-5/2),r= 7/2