What is x^2+y^2-15=y+2x ?

The solution to x^2+y^2-15=y+2x is Circle with (a,b)=(1, 1/2),r=(sqrt(65))/2

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x^2+y^2-15=y+2x

x^{2} + y^{2} - 15 = y + 2 x

(a, b) = (1, \frac{1}{2}), r = \frac{65}{2}

Solution steps

x^{2} + y^{2} - 15 = y + 2 x

Rewrite

x^{2} + y^{2} - 15 = y + 2 x

in the form of the standard circle equation

(x - 1)^{2} + (y - \frac{1}{2})^{2} = (\frac{65}{2})^{2}

Therefore the circle properties are:

(a, b) = (1, \frac{1}{2}), r = \frac{65}{2}

(x - 4)^{2} + y^{2} \leq 4

x^{2} + y^{2} = 48

(x - 2)^{2} + (y - 2)^{2} = 121

y^{2} + (x + 3)^{2} = 7

x^{2} + y^{2} = 23

What is x^2+y^2-15=y+2x ?
The solution to x^2+y^2-15=y+2x is Circle with (a,b)=(1, 1/2),r=(sqrt(65))/2