What is (x-11)^2+(y-3)^2=53 ?

The solution to (x-11)^2+(y-3)^2=53 is Circle with (a,b)=(11,3),r=sqrt(53)

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(x-11)^2+(y-3)^2=53

(x - 11)^{2} + (y - 3)^{2} = 53

(a, b) = (11, 3), r = 53

Solution steps

(x - 11)^{2} + (y - 3)^{2} = 53

Rewrite

(x - 11)^{2} + (y - 3)^{2} = 53

in the form of the standard circle equation

(x - 11)^{2} + (y - 3)^{2} = (53)^{2}

Therefore the circle properties are:

(a, b) = (11, 3), r = 53

(x + 2)^{2} + (y - 7)^{2} = 16

x^{2} + (y + 2)^{2} = 12

20 y^{2} + 20 x^{2} = 50

10 x^{2} + 10 y^{2} - 80 x + 200 y + 920 = 0

4 (x + 5)^{2} + 4 (y + 4)^{2} - 20 = 0

What is (x-11)^2+(y-3)^2=53 ?
The solution to (x-11)^2+(y-3)^2=53 is Circle with (a,b)=(11,3),r=sqrt(53)