What is x^2-2x+y^2= 436/5 ?

The solution to x^2-2x+y^2= 436/5 is Circle with (a,b)=(1,0),r=(21)/(sqrt(5))

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x^2-2x+y^2= 436/5

x^{2} - 2 x + y^{2} = \frac{436}{5}

(a, b) = (1, 0), r = \frac{21}{5}

Solution steps

x^{2} - 2 x + y^{2} = \frac{436}{5}

Rewrite

x^{2} - 2 x + y^{2} = \frac{436}{5}

in the form of the standard circle equation

(x - 1)^{2} + (y - 0)^{2} = (\frac{21}{5})^{2}

Therefore the circle properties are:

(a, b) = (1, 0), r = \frac{21}{5}

x^{2} + y^{2} + 5 x - 7 y - 17 = 0

z^{2} + y^{2} = 4

x^{2} + y^{2} + 14 y + 13 = 0

x^{2} + y^{2} - 2 x + 2 y - 1 = 0

(x + 9)^{2} + (y - 4)^{2} = 12

What is x^2-2x+y^2= 436/5 ?
The solution to x^2-2x+y^2= 436/5 is Circle with (a,b)=(1,0),r=(21)/(sqrt(5))